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GATE 2020 EC Q.33: official answer

GATE 2020 · ECQ.33 · 2 marks · MCQ

The base of an npn BJT T1 has a linear doping profile as shown below. The base of another npn BJT T2 has a uniform doping of . All other parameters are identical for both the devices. Assuming that the hole density profile is the same as that of doping, the common-emitter current gain of T2 is

GATE 2020 EC question 33: Doping profile of the base of T1.Tap to open full size
Figure from the GATE 2020 EC paper. It is part of the question.
Figure description

Doping profile of the base of T1. Two vertical dashed lines mark x = 0 (the Emitter/Base boundary) and x = W (the Base/Collector boundary) on a horizontal axis marked 0 and W, with the regions labelled Emitter, Base and Collector. A straight line labelled N_B(x) falls linearly from 10^17 (cm^-3) at x = 0 to 10^14 (cm^-3) at x = W. There is no labelled vertical axis; only these two values are marked.

  1. (A)

    approximately 2.0 times that of T1.

  2. (B)

    approximately 0.3 times that of T1.

  3. (C)

    approximately 2.5 times that of T1.

  4. (D)

    approximately 0.7 times that of T1.

Official answer

Official answer: marks to all candidatesSource: Official answer key, GATE 2020 EC (IIT Delhi)

From the GATE 2020 EC paper. Every question of this paper · Download the full paper · All 3 BJT questions, with notes

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