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GATE 2026 EE Q.59: solution and answer

GATE 2026 · EEQ.59 · 2 marks · NAT

A balanced three-phase supply is given to a 30 kW, 4-pole, 400 V, 50 Hz, wound rotor induction motor with Y-connected stator and rotor windings. The motor is driving a constant torque load. With shorted sliprings, the machine runs at 1476 rpm.

When an external non-inductive resistance of 0.27 Ω per phase is connected in series in the rotor circuit, the steady-state speed drops to 1404 rpm.

Neglecting rotational losses, the actual per phase rotor winding resistance is _____ Ω

(Round off to two decimal places)

See the question in the paper

Answer and solution

ANSWER

The actual per-phase rotor winding resistance is R₂ = 0.09 Ω.

Official answer: 0.09Source: Official answer key, GATE 2026 EE (IIT Guwahati)

  1. Synchronous speed:

  2. Slip with shorted sliprings:

  3. Slip with external resistance added:

  4. At low slip the torque expression reduces to (the term is negligible), so for the same constant-torque load before and after inserting :

  5. Cross-multiplying:

  6. Solve for :

KEY IDEA

For a constant-torque load driven at low slip, torque is approximately proportional to s/R₂ (the sX₂ term in the torque expression is negligible at low slip), so equal torque before and after adding rotor resistance gives s₁/R₂ = s₂/(R₂+r), which can be solved directly for the unknown rotor resistance R₂.

WATCH OUT FOR

Forgetting to neglect the sX₂ term (i.e., trying to use the full torque expression with an unknown X₂, which the problem gives no way to determine) or mixing up which resistance (R₂ vs R₂+r) goes with which slip, both of which make the problem unsolvable or give a wrong sign on r.

From the GATE 2026 EE paper. Every question of this paper · Download the full paper · All 17 Induction machines questions, with notes

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