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IN THE EC SYLLABUS

Transmission lines

Transmission lines, impedance matching, S-parameters and the Smith chart

A transmission line is a circuit long enough, compared with the wavelength, that voltage and current travel along it as waves, described by the line's characteristic impedance and propagation constant . The working method is the same throughout the topic: turn the load into a reflection coefficient, rotate that coefficient by to move a distance along a lossless line, and add a line section or stub that cancels the reflection. The Smith chart does the same work graphically, and S-parameters describe a whole network in the same language of incident and reflected waves.

13 previous-year questions · 13 solved · 5 practice questions

Line equations and line constants

Conventions used throughout. SI units, with H/m, F/m, m/s and . Phasors are peak values with time dependence , so time-average power is . The line lies along , with the generator on the left and the load at ; is the distance measured from the load toward the generator. , , , are the per-unit-length series resistance (/m), series inductance (H/m), shunt conductance (S/m) and shunt capacitance (F/m). A wave travelling toward the load (the direction) varies as , and on a lossless line as . always means the voltage reflection coefficient, at the load. Impedances and admittances normalised to the line are written in lower case (, , and on the Smith chart); a bare in the line equations is the position.

A short piece of line is a series , followed by a shunt , . Applying KVL and KCL to it and letting gives the telegrapher's equations. Eliminating one variable gives a wave equation, whose solutions are two travelling waves, one going each way.

TELEGRAPHER'S EQUATIONS (TIME DOMAIN)

KVL and KCL on a section as ; valid for any waveform.

TELEGRAPHER'S EQUATIONS (PHASOR FORM)

Sinusoidal steady state with ; the third equation follows by differentiating the first and substituting the second.

GENERAL SOLUTION

is the wave travelling toward the load and the reflected wave. The minus sign in matters: the reflected wave's current flows back toward the generator.

PROPAGATION CONSTANT AND CHARACTERISTIC IMPEDANCE

in Np/m (1 Np = 8.686 dB), in rad/m. for ONE travelling wave; it is not at a point on a mismatched line. Inverting, and recover the line constants from measured and .

LOSSLESS LINE ($R = G = 0$)

is real and, with and constant, independent of frequency. On any TEM line whose dielectric is homogeneous (coaxial, two-wire, parallel-plate) ; for a non-magnetic dielectric of relative permittivity this gives , so the wavelength on the line is shorter than in free space by the factor .

DISTORTIONLESS LINE (HEAVISIDE CONDITION)

The line is lossy, but (taking , , , as constants) and do not depend on frequency and is real, so a signal is attenuated and delayed without changing shape.

LOW-LOSS APPROXIMATION

The first term of is conductor loss, the second dielectric loss.

COAXIAL LINE

Inner conductor radius , inner radius of the outer conductor , lossless dielectric with and . is the external inductance only (internal inductance neglected, as at high frequency where the current flows in a thin skin); the last form uses .

TWO-WIRE AND PARALLEL-PLATE LINES

Two-wire: conductor radius , centre-to-centre spacing ; for , , so for a non-magnetic dielectric. Parallel-plate: strip width and separation , with so that fringing can be neglected. Both, like the coaxial line, satisfy (external inductance, lossless dielectric).

WORKED EXAMPLE

A transmission line has , nH/m and pF/m, and operates at MHz. (a) Find the shunt conductance that makes it distortionless. (b) With that , find , , , and the wavelength on the line. (c) By how many dB is a signal attenuated over 50 m?

Solution
  1. Distortionless condition : S/m.

  2. , real, as on every distortionless line.

  3. Np/m.

  4. m/s, so m and rad/m.

  5. Over 50 m: Np dB. (The exact evaluates to per metre, confirming both numbers.)

Answer: mS/m; , Np/m, rad/m, m/s, m; about 4.34 dB over 50 m.

EXAM TIP

Distortionless does not mean lossless. The Heaviside line still has ; what it removes is the frequency dependence of and . is set by the line itself (its geometry, its materials and, on a lossy line, the frequency), never by its length or by the load.

Terminated line: reflection, VSWR, return loss and input impedance

At the load the total voltage and current must satisfy . A single incident wave, for which , can do this only if ; otherwise a reflected wave appears. The ratio of reflected to incident voltage at a point is the reflection coefficient. On a lossless line its magnitude is the same everywhere, and its phase falls by as you move a distance toward the generator, because the reflected wave travels out and back.

LOAD REFLECTION COEFFICIENT

Voltage reflection coefficient; for any passive load () on a line with real . The current reflection coefficient is .

TRANSMISSION COEFFICIENT AT A JUNCTION

Voltage is continuous at the load or junction, so transmitted voltage = incident + reflected. For a junction the 'load' is the second line's (assumed matched beyond). can exceed 1, but power still balances: for real , the fraction of incident power transmitted is .

REFLECTION COEFFICIENT ALONG THE LINE

and is measured from the load toward the generator. On a lossy line shrinks as toward the generator.

VOLTAGE AND CURRENT ON A LOSSLESS LINE

is largest where is real and positive, and smallest where it is real and negative; does the opposite.

INPUT IMPEDANCE OF A LOSSLESS LINE

Every input-impedance result in the next section is a special case of this formula. repeats every , because has period .

INPUT IMPEDANCE OF A LOSSY LINE

Here and are in general complex. With it reduces to the lossless form, because .

VOLTAGE STANDING WAVE RATIO

Lossless line: and . The current maxima sit at the voltage minima.

RETURN LOSS, DELIVERED POWER AND MISMATCH LOSS

Lossless line, a peak phasor. is the fraction of incident power reflected. The same delivered power is . Return loss is quoted here as a positive number for a passive load (a matched load has ); some texts attach a minus sign, so read the question's convention.

LINE DRIVEN BY A GENERATOR

is the source's open-circuit voltage (peak phasor) and its internal impedance; is the input impedance of the line together with its load. On a lossless line all of reaches the load. For a given source, is largest when (conjugate matching); when is real, that happens exactly when the load is matched, .

STEP RESPONSE OF A LOSSLESS LINE (RESISTIVE SOURCE AND LOAD)

A step of height is applied at through a source resistance to a line of one-way delay . The line first looks like , so it launches . At this reaches the load, which reflects , so the load voltage jumps to ; at the reflection reaches the source and is reflected again with , and so on. The voltage at any point is the sum of every wave that has passed it so far (a bounce diagram). The final value is the DC voltage divider, because at DC a lossless line is just a pair of wires.

POSITIONS OF VOLTAGE MAXIMA AND MINIMA

Lossless line, in radians, an integer; the first maximum (or minimum) is the smallest the formula gives. Successive maxima (or minima) are apart and a maximum is from the next minimum. The line impedance is purely resistive at both.

LOAD FROM MEASURED VSWR AND A VOLTAGE MINIMUM

The slotted-line measurement on a lossless line: is the distance from the load to any voltage minimum; follows from .

Standard loads on a lossless line

Load

VSWR

At the load

(matched)

no standing wave; the same everywhere

real, positive

voltage maximum

real, negative

voltage minimum

Short circuit,

voltage zero, current maximum

Open circuit,

voltage maximum, current zero

Pure reactance,

neither a maximum nor a minimum (for )

WORKED EXAMPLE

A lossless line is terminated in . Find , the VSWR, the return loss and the fraction of incident power reflected. Locate the first voltage maximum and the first voltage minimum from the load, and give the line impedance at each.

Solution
  1. . Multiply top and bottom by : numerator , denominator . So .

  2. VSWR: . Return loss dB. Reflected fraction , about 11.1%.

  3. First maximum where : . Since , . The first minimum is further on, at .

  4. and . Check with the input-impedance formula at , where : .

Answer: , , dB, 11.1% of the incident power reflected; first at (), first at ().

EXAM TIP

Moving a distance along the line turns through , not . So is half a turn and is a full turn. Using for the rotation is a common slip.

EXAM TIP

Use the wavelength ON the line, , which is for a TEM line filled with a non-magnetic dielectric. A 'quarter-wave' section of dielectric-filled cable is physically shorter than .

Special cases: short, open, matched, quarter-wave and half-wave lines

Putting special loads or special lengths into the input-impedance formula gives results that are used again and again in stub and transformer design. All results below are for a lossless line of length at the operating frequency.

SHORT-CIRCUITED LINE

Purely reactive. Inductive for (with at ); an open circuit at , near which it behaves like a parallel resonant circuit; capacitive for ; a short circuit again at .

OPEN-CIRCUITED LINE

Purely reactive. Capacitive for (with at ); a short circuit at , near which it behaves like a series resonant circuit; inductive for ; an open circuit again at .

LINE CONSTANTS FROM OPEN- AND SHORT-CIRCUIT MEASUREMENTS

Valid for lossy lines too, since and ; take the root of with . For a lossless line write and : then and , which fixes to within a multiple of . (Taking loses the sign: a line would be read as .)

QUARTER-WAVE LINE (IMPEDANCE INVERTER)

A short becomes an open, an open becomes a short, and an inductive load looks capacitive (and vice versa).

HALF-WAVE LINE

For any : at a frequency where the section is a whole number of half-wavelengths long, it repeats the load impedance.

MATCHED LINE

No reflected wave; and are the same everywhere and the VSWR is 1.

What a lossless line section looks like

Line section

Short-circuited

inductive

open circuit

capacitive

short circuit

Open-circuited

capacitive

short circuit

inductive

open circuit

Terminated in

depends on

depends on

Matched,

EXAM TIP

To make a short-circuited stub present a reactance , set . Within the first half-wavelength, a capacitive reactance () needs ; an open-circuited stub shorter than , with , does the same job with a shorter piece of line.

EXAM TIP

Quarter-wave and half-wave properties hold only at the frequency at which the section is exactly or long. At twice that frequency a quarter-wave section becomes a half-wave section and simply repeats the load.

Impedance matching: quarter-wave transformer and single stub

Matching removes the reflected wave from the line between the generator and the matching network, so with a lossless network all the power incident on it reaches the load and the VSWR on that part of the line is 1. A standing wave still exists between the matching network and the load; matching confines it there.

QUARTER-WAVE TRANSFORMER (REAL LOAD)

A section of characteristic impedance makes a real load look like . Exact only at the design frequency (where the section is long) and at odd multiples of it.

QUARTER-WAVE TRANSFORMER FOR A COMPLEX LOAD

First move from the load to a point where the line impedance is real ( at , at ), cut the line there and insert the section: or .

ADMITTANCE TRANSFORMATION ALONG A LOSSLESS LINE

Same form as the impedance formula, written in normalised admittances. Use it whenever elements are connected in shunt.

Single-stub (shunt) matching: procedure

  1. Normalise and invert: . A shunt stub adds admittance, so work in admittances.

  2. Move a distance toward the generator until the real part of the line admittance is 1: . For any load with there are two such points in every .

  3. At that point connect, in parallel, a stub whose input admittance is , so the total is .

  4. Short-circuited stub (same ): , so . Open-circuited stub: , so . Add to any negative length.

  5. Where one of the two solutions has both the smaller and the shorter stub, it is normally preferred, because shorter lengths make the match less sensitive to frequency.

SHUNT-STUB POSITION FOR A RESISTIVE LOAD

Lossless line; the upper signs go together. Obtained by setting with . Take in , adding to a negative angle.

WORKED EXAMPLE

A lossless line feeds a load . It is to be matched with a single short-circuited shunt stub, also of line. Find the distance from the load to the stub and the stub length for both solutions within the first half-wavelength.

Solution
  1. , so .

  2. Try : a quarter-wave section inverts the normalised admittance, . The real part is already 1, so this is a solution with .

  3. The stub at this point must supply : , , (an inductive short stub, as it must be for ).

  4. Second solution: with , , whose real part is . Setting this equal to 1 leaves , so (the limit is the point already found).

  5. , so . There .

  6. The stub must now supply : , , .

Answer: Solution 1: , . Solution 2: , . Solution 1 is shorter on both counts.

EXAM TIP

A quarter-wave transformer cannot match a complex load directly: would be complex, and a lossless line has a real . Either move to a voltage maximum or minimum first, or cancel the load reactance before the transformer.

EXAM TIP

Shunt stub: work in admittances, look for , stub gives . Series stub: work in impedances, look for , stub gives . Mixing the two is an easy error to make.

The Smith chart

The Smith chart is the complex -plane inside the unit circle , with circles of constant normalised resistance and constant normalised reactance drawn on it, where . Because moving along a lossless line only rotates , every 'move a distance ' step becomes a rotation about the centre at constant radius .

THE MAPPING BEHIND THE CHART

The centre of the chart is , the matched point .

CONSTANT-RESISTANCE CIRCLES

Centre , radius ; every one passes through . is the outer rim and passes through the centre.

CONSTANT-REACTANCE CIRCLES

Centre , radius ; only the arcs inside the unit circle are drawn. arcs lie in the upper half, in the lower half, and is the horizontal axis.

ROTATION FOR A MOVE ALONG THE LINE

With the convention: clockwise when moving toward the generator, counter-clockwise toward the load. One full turn is , so the rim scales run from 0 to 0.5 wavelengths.

Smith chart landmarks (impedance reading)

Point or region

Where on the chart

Meaning

centre

matched,

left end of the horizontal axis

short circuit,

right end of the horizontal axis

open circuit,

Outer circle

, i.e.

pure reactance (input of a lossless stub)

Upper half

inductive,

Lower half

capacitive,

Horizontal axis, right of centre

,

voltage maximum; where the constant- circle crosses it,

Horizontal axis, left of centre

,

voltage minimum; where the constant- circle crosses it,

Standard Smith chart moves

  1. Plot where its circle and arc cross; draw the constant- circle through it, centred on the chart centre.

  2. Read as (distance from the centre) divided by (radius of the chart) and on the angle scale; read the VSWR where the circle cuts the horizontal axis to the right of the centre.

  3. To find a distance from the load, rotate clockwise by on the 'wavelengths toward generator' scale, staying on the circle, and read ; multiply by .

  4. To convert an impedance to an admittance, go to the diametrically opposite point on the same circle (, which is a move), because corresponds to .

  5. For the distance from the load to the first voltage minimum, rotate clockwise from to the horizontal axis left of the centre; for the first maximum, to the axis right of the centre.

  6. On a lossy line the point spirals inward toward the centre as you move toward the generator, since falls as .

Reading the chart as an admittance chart. Plot on the same circles, which are then constant- circles and constant- arcs. In this reading the upper half means capacitive susceptance (), the right end of the axis is (a short circuit) and the left end is (an open circuit); moving toward the generator is still clockwise. A short-circuited stub therefore starts at the right end: turning clockwise from there () lands on , the stub used in the matching example above.

EXAM TIP

Any Smith chart result can be checked by calculation: rotate with , then convert with . For a numerical-answer question, compute rather than read the chart; a chart reading is only as precise as the drawing.

EXAM TIP

The admittance point lies round the chart, which is a move along the line. That is the Smith chart picture of the quarter-wave inverter .

S-parameters of a two-port

At microwave frequencies ideal opens and shorts are hard to make, so a network is described by how it scatters travelling waves when its ports are terminated in matched loads. Convention: every port uses the same real reference impedance ; with peak phasors, is the power incident on port and the power leaving it. The definitions extend to any number of ports; the two-port is written out here.

INCIDENT AND REFLECTED WAVE VARIABLES

enters port , leaves it. The net time-average power into port is .

DEFINITION OF THE SCATTERING MATRIX

is the reflection coefficient at port 1 with port 2 terminated in (matched, not shorted); is the transmission coefficient from port 1 to port 2 under the same condition.

INPUT REFLECTION COEFFICIENT WITH AN ARBITRARY LOAD

is the reflection coefficient of the load on port 2, referred to . only when . Looking back into port 2 with a source of reflection coefficient on port 1, .

RETURN LOSS, INSERTION LOSS AND INPUT VSWR

All with port 2 matched. is the fraction of the incident power delivered to the matched load on port 2.

RECIPROCITY

Holds for linear networks built only from reciprocal elements (line sections, R, L, C, coupled coils and transformers), with the same real reference impedance at both ports. Fails for magnetically biased ferrite devices (isolators, circulators) and for active circuits such as amplifiers.

LOSSLESSNESS (UNITARY S-MATRIX)

Each column carries unit power and different columns are orthogonal (equivalently, , so the rows are too). For a lossless two-port this forces and . Any passive network has ; the shortfall is the fraction of the power incident on port 1 that is dissipated inside the network (port 2 matched).

SERIES IMPEDANCE $Z$ BETWEEN THE PORTS

Port 1 sees when port 2 is matched.

SHUNT ADMITTANCE $Y$ ACROSS THE PORTS

Here because the voltage is the same on both sides of a shunt element.

MATCHED LOSSLESS LINE SECTION AND REFERENCE-PLANE SHIFT

A line of the reference impedance and length . Moving the reference plane at port outward by a length of matched line changes only phases: .

Properties of some standard networks (same reference impedance at every port)

Network

S-parameters (up to phase factors)

Reciprocal?

Lossless?

Matched lossless line section

,

yes

yes

Matched attenuator of dB

,

yes

no

Series reactance or shunt susceptance

the two formulas above

yes

yes

Ideal isolator (passes port 1 to port 2)

,

no

no: power entering port 2 is absorbed

Ideal three-port circulator ()

, all others

no

yes

WORKED EXAMPLE

A resistor is connected in series between port 1 and port 2 of a system. Find its S-parameters, state whether it is reciprocal and whether it is lossless, find the return loss and insertion loss, and account for all of the incident power.

Solution
  1. With port 2 terminated in , port 1 sees : . By symmetry .

  2. The voltage at port 1 is . The divider gives , and with port 2 matched , so (the same as ). By symmetry .

  3. Reciprocal, since . Not lossless: .

  4. Power balance: of the incident power is reflected, reaches the port-2 load, and the remaining is dissipated in the series resistor. That is consistent: the resistor carries the same current as the load and has the same resistance.

  5. Return loss dB; insertion loss dB.

Answer: , ; reciprocal but lossy; return loss 9.54 dB, insertion loss 3.52 dB; power split 1/9 reflected, 4/9 delivered, 4/9 dissipated.

EXAM TIP

Reciprocal and lossless are independent tests. Reciprocity is symmetry (); losslessness is unitarity. A resistive attenuator is reciprocal but lossy; an ideal ferrite circulator is lossless but not reciprocal.

EXAM TIP

Use on (a wave-amplitude ratio) or on (a power ratio); both give the same dB figure. Writing halves the answer.

PREVIOUS-YEAR QUESTIONS

13 questions from the EC papers

Try each question first, then open the answer. We placed each question under a topic ourselves; the exam paper does not label topics.

See these papers in full: GATE ECE 2026 · GATE ECE 2025 · GATE ECE 2024 · GATE ECE 2023 · GATE ECE 2020 · GATE ECE 2018

GATE 2026 EC Q.34

GATE 2026 · ECQ.34 · 1 mark · NAT

For a lossless passive two-port network, and intersect at dB.

For a lossy passive two-port network, and intersect at dB.

The percentage of power dissipated in the lossy network at the intersection frequency is ____. (rounded off to two decimal places)

Answer and solution
See the question in the paper
GATE 2026 EC Q.34: answer and solution

GATE 2026 EC Q.52

GATE 2026 · ECQ.52 · 2 marks · MCQ

A complex load (in ) is represented as on the Smith chart.

A co-axial cable with a characteristic impedance of is connected to the load.

The new input impedance of the load now moves to a diametrically opposite point on the same circle on the Smith chart.

Which option is the nearest input impedance of the cable connected load (in )?

  1. (A)

  2. (B)

  3. (C)

  4. (D)

Answer and solution
See the question in the paper
GATE 2026 EC Q.52: answer and solution

GATE 2024 EC Q.15

GATE 2024 · ECQ.15 · 1 mark · MCQ

Consider a lossless transmission line terminated with a short circuit as shown in the figure below. As one moves towards the generator from the load, the normalized impedances , , , and (indicated in the figure) are ________.

GATE 2024 EC question 15: A two-wire lossless transmission line drawn horizontally (two thick parallel lines).Tap to open full size
Figure from the GATE 2024 EC paper. It is part of the question.
Figure description

A two-wire lossless transmission line drawn horizontally (two thick parallel lines). At the right end (z = 0) the two conductors are joined by a vertical wire, i.e. a short-circuit load. A z-axis runs left to right beneath the line, with the right end marked 0 and the left end marked -l. Vertical dashed lines divide the line into four equal segments, each labelled λ/8 with double-headed arrows along the top. Moving from the load (z = 0) towards the generator (left): the first dashed line (distance λ/8 from the load) is labelled z_inA, the second (distance λ/4) is labelled z_inB, the third (distance 3λ/8) is labelled z_inC, and the fourth, at the left end z = -l (distance λ/2), is labelled z_inD. Each label has a right-pointing bent arrow indicating the impedance looking towards the load.

  1. (A)

    , , ,

  2. (B)

    , , ,

  3. (C)

    , , ,

  4. (D)

    , , ,

Answer and solution
GATE 2024 EC Q.15: answer and solution

GATE 2024 EC Q.58

GATE 2024 · ECQ.58 · 2 marks · NAT

A lossless transmission line with characteristic impedance is terminated with an unknown load. The magnitude of the reflection co-efficient is . As one moves towards the generator from the load, the maximum value of the input impedance magnitude looking towards the load (in ) is ________.

Answer and solution
See the question in the paper
GATE 2024 EC Q.58: answer and solution

GATE 2023 EC Q.51

GATE 2023 · ECQ.51 · 2 marks · MCQ

The S-parameters of a two port network is given as

with reference to . Two lossless transmission line sections of electrical lengths and are added to the input and output ports for measurement purposes, respectively. The S-parameters of the resultant two port network is

GATE 2023 EC question 51: A box labelled [S] in the centre (the original two-port).Tap to open full size
Figure from the GATE 2023 EC paper. It is part of the question.
Figure description

A box labelled [S] in the centre (the original two-port). On its left, a two-wire transmission line section of characteristic impedance Z_0 is attached to port 1. Its outer (far-left) terminals are marked z_1 = l_1 and the terminals where it meets the [S] box are marked z_1 = 0 (dashed vertical reference line). A double-headed arrow above this left section is labelled theta_1 = beta l_1. On the right, a second two-wire line section of characteristic impedance Z_0 is attached to port 2. The terminals at the box are marked z_2 = 0 (dashed vertical reference line) and the outer (far-right) terminals are marked z_2 = l_2. A double-headed arrow above it is labelled theta_2 = beta l_2. A dotted rectangle encloses both line sections and the [S] box, and is labelled [S'] beneath it: the new two-port whose reference planes are at z_1 = l_1 and z_2 = l_2.

  1. (A)

  2. (B)

  3. (C)

  4. (D)

Answer and solution
GATE 2023 EC Q.51: answer and solution

GATE 2023 EC Q.52

GATE 2023 · ECQ.52 · 2 marks · MSQ

The standing wave ratio on a 50 lossless transmission line terminated in an unknown load impedance is found to be 2.0. The distance between successive voltage minima is 30 cm and the first minimum is located at 10 cm from the load. can be replaced by an equivalent length and terminating resistance of the same line. The value of and , respectively, are

GATE 2023 EC question 52: Two transmission lines, one drawn above the other.Tap to open full size
Figure from the GATE 2023 EC paper. It is part of the question.
Figure description

Two transmission lines, one drawn above the other. Each is a pair of horizontal parallel wires labelled Z_0, with open input terminals (dots) at the left end. Upper line: its wires end at the plane z = 0 (dots on both wires) and are joined there to a box labelled Z_L. Lower line: the same line Z_0 carries on past the plane z = 0 for a further length l_m (a double-headed arrow from z = 0 to the right end, labelled l_m) and ends in a resistor (zigzag symbol) labelled R_m. Two vertical dashed lines cross both lines. The right one is at z = 0, the load plane of the upper line. The left one, a short way towards the input, is labelled z = z_m. The labels z = z_m and z = 0 are printed under the lower line. Not to scale.

  1. (A)

    , cm

  2. (B)

    , cm

  3. (C)

    , cm

  4. (D)

    , cm

Answer and solution
GATE 2023 EC Q.52: answer and solution

GATE 2023 EC Q.54

GATE 2023 · ECQ.54 · 2 marks · MSQ

The following circuit(s) representing a lumped element equivalent of an infinitesimal section of a transmission line is/are

GATE 2023 EC question 54: Each option is a two-port with a top (signal) wire and a bottom (return) wire, input terminals on the left and output…Tap to open full size
Figure from the GATE 2023 EC paper. It is part of the question.
Figure description

Each option is a two-port with a top (signal) wire and a bottom (return) wire, input terminals on the left and output terminals on the right. (A) Top wire: series inductor L Δ z followed by series resistor R Δ z. Shunt branches: a capacitor C Δ z/2 across the input side (before the inductor) and a resistor (conductance) G Δ z/2 across the output side (after the resistor). There is no shunt G at the input and no shunt C at the output. (B) Shunt conductance G Δ z and shunt capacitor C Δ z in parallel across the input terminals, then series inductor L Δ z and series resistor R Δ z on the top wire to the output (L-section). (C) Shunt G Δ z/2 and C Δ z/2 in parallel across the input, series L Δ z and R Δ z on the top wire, then shunt G Δ z/2 and C Δ z/2 in parallel across the output (pi-section). (D) Top wire: series R Δ z/2, series L Δ z/2, then at the midpoint a shunt G Δ z in parallel with C Δ z to the bottom wire, then series L Δ z/2 and series R Δ z/2 to the output (T-section).

  1. (A)

    Figure — series and ; shunt only at the input side and shunt only at the output side

  2. (B)

    Figure — shunt at the input, followed by series and

  3. (C)

    Figure — shunt at the input, series and , shunt at the output

  4. (D)

    Figure — series and , shunt at the middle, series and

Answer and solution
GATE 2023 EC Q.54: answer and solution

GATE 2020 EC Q.46

GATE 2020 · ECQ.46 · 2 marks · NAT

For a 2-port network consisting of an ideal lossless transformer, the parameter (rounded off to two decimal places) for a reference impedance of , is ________.

GATE 2020 EC question 46: A dashed rectangle labelled "2 Port Network" at the top holds an ideal transformer drawn as two coupled coils side by…Tap to open full size
Figure from the GATE 2020 EC paper. It is part of the question.
Figure description

A dashed rectangle labelled "2 Port Network" at the top holds an ideal transformer drawn as two coupled coils side by side: the left (primary) coil connects to a top-left and a bottom-left terminal (open circles), and the right (secondary) coil connects to a top-right and a bottom-right terminal (open circles). The turns ratio "2:1" (primary: secondary) is printed below the coils inside the dashed box. No polarity dots are drawn. On the left, a dashed bracket with an arrow pointing right into the left terminal pair is labelled "Port 1". On the right, a dashed bracket with an arrow pointing left into the right terminal pair is labelled "Port 2".

Answer and solution
GATE 2020 EC Q.46: answer and solution

GATE 2018 EC Q.10

GATE 2018 · ECQ.10 · 1 mark · MCQ

The points , , and shown on the Smith chart (normalized impedance chart) in the following figure represent:

GATE 2018 EC question 10: A normalized-impedance Smith chart drawn in outline.Tap to open full size
Figure from the GATE 2018 EC paper. It is part of the question.
Figure description

A normalized-impedance Smith chart drawn in outline. The outer unit circle (| Γ | = 1) is shown, with a horizontal diameter (the real axis, x = 0) running from the leftmost point to the rightmost point. A smaller circle passes through the chart centre and the rightmost point (the r = 1 constant-resistance circle). Two arcs run from the top and bottom of the outer circle to the rightmost point (the x = +1 arc in the upper half and the x = -1 arc in the lower half). Three points are marked with a circled cross: P at the leftmost end of the horizontal diameter, Q at the centre of the chart (where the r = 1 circle meets the real axis on its left side), and R at the rightmost end of the horizontal diameter, where all the circles and arcs meet.

  1. (A)

    P: Open Circuit, Q: Short Circuit, R: Matched Load

  2. (B)

    P: Open Circuit, Q: Matched Load, R: Short Circuit

  3. (C)

    P: Short Circuit, Q: Matched Load, R: Open Circuit

  4. (D)

    P: Short Circuit, Q: Open Circuit, R: Matched Load

Answer and solution
GATE 2018 EC Q.10: answer and solution

PRACTICE

5 questions to test yourself

PRACTICE 11 mark · MCQ

A lossless line of length is short-circuited at its far end. At the operating frequency, its input impedance is

  1. (A)

    (inductive)

  2. (B)

    (capacitive)

  3. (C)

    an open circuit

  4. (D)

    (inductive)

Answer and solution

Answer: (B)

  1. .

  2. : capacitive, as expected for a short stub between and .

  3. Smith chart check: start at the short, , and turn clockwise, landing at , i.e. .

  4. Option D is the value obtained by wrongly using .

PRACTICE 22 marks · NAT

A lossless line is terminated in a load . The load is to be matched by cutting the main line at the voltage minimum nearest to the load and inserting a quarter-wave section of lossless line there. The characteristic impedance of the quarter-wave section, in , is ______ (round off to two decimal places).

Answer and solution

Answer: (accepted range )

  1. , so and .

  2. First minimum where : , so .

  3. VSWR , so the line impedance at the minimum is . Check at (): .

  4. .

PRACTICE 32 marks · MSQ

A two-port network, characterised with a reference impedance at both ports, has the scattering matrix . Which of the following statements is/are correct?

  1. (A)

    The network is reciprocal.

  2. (B)

    The network is lossless.

  3. (C)

    With port 2 terminated in a matched load, the return loss at port 1 is approximately 4.44 dB.

  4. (D)

    With port 2 terminated in a matched load, the insertion loss from port 1 to port 2 is approximately 0.97 dB.

Answer and solution

Answer: (A), (B), (C)

  1. , so the network is reciprocal: A is correct.

  2. Column 1: ; column 2 is the same. Orthogonality: . The matrix is unitary, so the network is lossless: B is correct.

  3. Return loss dB: C is correct.

  4. Insertion loss dB. The figure 0.97 dB comes from wrongly using : D is incorrect.

PRACTICE 42 marks · NAT

A lossless line is terminated in a resistor. The load is to be matched with a single short-circuited shunt stub made of the same line. For the solution in which the stub is attached closest to the load, the length of the shortest such stub, in wavelengths, is ______ (round off to three decimal places).

Answer and solution

Answer: (accepted range )

  1. , so .

  2. With : .

  3. Real part : , so and (that is, with ).

  4. Closest to the load: , , . There the imaginary part is , so .

  5. The stub must supply : , so and .

  6. . (The other solution, at , needs a stub.)

PRACTICE 51 mark · NAT

A lossless line is terminated in a load . The voltage standing wave ratio on the line is ______ (round off to two decimal places).

Answer and solution

Answer: (accepted range )

  1. .

  2. .

  3. .

OFFICIAL GATE 2027 SYLLABUS WORDING

Copied from the GATE 2027 syllabus; see all 2027 syllabi.

GATE EC

Transmission Lines: Equations, characteristic impedance, impedance matching, impedance transformation, Sparameters, Smith chart

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